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Basic Properties of Circles: practice questions

6 questions · 11 marks · free, no account · Read the notes first

  1. Question 1Multiple choice · 1 mark

    OO is the centre of a circle. AA, BB and CC lie on the circle, with CC on the major arc ABAB. If ∠AOB=130°\angle AOB = 130°, find ∠ACB\angle ACB.

  2. Question 2Multiple choice · 1 mark

    ABCDABCD is a cyclic quadrilateral with ∠A=72°\angle A = 72°. Find ∠C\angle C.

  3. Question 3Multiple choice · 1 mark

    A chord of length 16 cm is 6 cm from the centre of a circle. Find the radius of the circle.

  4. Question 4Multiple choice · 1 mark

    ABAB is a diameter of a circle and CC is a point on the circle. If ∠CAB=35°\angle CAB = 35°, find ∠CBA\angle CBA.

  5. Question 54 marks

    TATA and TBTB are tangents to a circle with centre OO, touching it at AA and BB. If ∠ATB=50°\angle ATB = 50°, find ∠AOB\angle AOB and ∠OAB\angle OAB, giving reasons.

    Show worked solution

    ∠OAT=∠OBT=90°\angle OAT = \angle OBT = 90° (tangent ⊥ radius) 1A

    ∠AOB=360°−90°−90°−50°=130°\angle AOB = 360° - 90° - 90° - 50° = 130° (∠ sum of polygon) 1A

    OA=OBOA = OB (radii), so ∠OAB=∠OBA\angle OAB = \angle OBA (base ∠s, isos. △) 1M

    ∠OAB=180°−130°2=25°\angle OAB = \dfrac{180° - 130°}{2} = 25° (∠ sum of △) 1A

  6. Question 63 marks

    TATA is the tangent to a circle at AA. ABAB is a chord and CC is a point on the circle on the opposite side of ABAB from TT. If ∠TAB=68°\angle TAB = 68° and ∠CAB=47°\angle CAB = 47°, find ∠ACB\angle ACB and ∠ABC\angle ABC, giving reasons.

    Show worked solution

    ∠ACB=∠TAB=68°\angle ACB = \angle TAB = 68° 1A

    (∠ in alt. segment) 1A

    ∠ABC=180°−68°−47°=65°\angle ABC = 180° - 68° - 47° = 65° (∠ sum of △) 1A

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