logay=x means exactly the same as ax=y. The common logarithm logy means log10y.
Law
loga(MN)=logaM+logaN
product
logaNM=logaM−logaN
quotient
logaMn=nlogaM
power
logab=logalogb
change of base
Also loga1=0 and logaa=1.
Common mistake:log(M+N) is notlogM+logN, and logNlogM is notlogM−logN.
Graphs
y=ax (a>0, a=1) passes through (0,1) and always lies above the x-axis. It increases when a>1 and decreases when 0<a<1.
y=logax passes through (1,0) and is defined only for x>0.
y=ax and y=logax are reflections of each other in the line y=x.
Solving exponential equations
Take logs of both sides:
3x=20⇒xlog3=log20⇒x=log3log20≈2.73
Linear relations with logarithms
If y=kax, taking logs gives logy=logk+xloga, so the graph of logy against x is a straight line with slope loga and intercept logk. DSE often gives such a straight-line graph and asks you to express y in terms of x.
Real-life models
Growth or decay at a fixed rate r per period: A=P(1±r)t. For example, a car losing 15% of its value every year is worth P(0.85)t after t years.
Exam tip: when a question asks "after how many full years", solve the inequality, then round up to the next whole number and check it.
In the DSE exam
Syllabus scope
You need: laws of integral and rational indices, logarithms and their laws, change of base, graphs of exponential and logarithmic functions, solving exponential and logarithmic equations, the linear relation between logy and x, and real-life applications.
Not needed: the natural logarithm lnx and ex (these are in Module 1 and Module 2).
How it is tested
Paper 2 MC: simplify expressions with logs; pick the graph of y=ax or y=logax; "The graph shows a linear relation between log2y and x ... Express y in terms of x."
Paper 1: growth and decay problems, often asking for the least number of years.
How to answer
Take logs of both sides and show the step: it earns the method mark.
Remember that log0.85<0: dividing by it reverses the inequality sign.
Give answers correct to 3 significant figures unless the question says otherwise.